Showing posts with label TCS Pattern 7. Show all posts
Showing posts with label TCS Pattern 7. Show all posts

Monday, January 23, 2012

TCS Aptitude Pattern 7

Pattern 7:

1. (40*40*40 – 31*31*31)/(40*40+40*31+31*31)=?

a)8 b)9 c)71 d)51

Hints:a3 -b3 =(a-b)*(a2+a*b+b2) so from this formula we will find (a-b) value