TCS Aptitude Pattern 7

Pattern 7:

1. (40*40*40 – 31*31*31)/(40*40+40*31+31*31)=?

a)8 b)9 c)71 d)51

Hints:a3 -b3 =(a-b)*(a2+a*b+b2) so from this formula we will find (a-b) value

2. (98*98*98 – 73*73*73)/( 98*98*98 – 73*73*73)=?

a).171 b).4 c).420 d).415

3. (209*144)^2 + (209*209)+(209*144)+(144*144) = ?

a)905863729 b)905368729 c)905729368 d)65

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Posted in: Algebra,Sample Papers,TCS,TCS Pattern 7,Verbal