Output & Errors

void main()

{

  char s[ ]="man";

  int i;

  for( i=0 ; s[ i ] ; i++ )

   printf("\n%c %c %c %c" , s[ i ], *(s + i), *(i + s), i[s]);

}

Output:

m m m m

a a a a

n n n n

Since, 's' contains the base address and 'i' is the index i.e the address after 'i' locations from the base address. Internally C compiler converts the statement s[ i ] into the form *(s + i), which equals *(i + s) or can also be written as i[s].

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Posted in: Array,C,Output n Errors in C,Pointers,Technical